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Answer:

SQL (Structured Query Language) is a standard programming language used for managing and manipulating relational databases.

Example: 
SELECT * FROM table_name;
Answer:

SQL commands are categorized into four types: DDL (Data Definition Language), DML (Data Manipulation Language), DCL (Data Control Language), and TCL (Transaction Control Language).

Example:

	DDL: CREATE TABLE table_name (column1 datatype, column2 datatype);
	DML: INSERT INTO table_name (column1, column2) VALUES (value1, value2);
	DCL: GRANT SELECT ON table_name TO user;
	TCL: COMMIT;
Answer:

A database is an organized collection of structured information or data, typically stored electronically in a computer system.

Answer: A primary key is a unique identifier for a record in a table, ensuring that no two rows have the same value.
        
Example: 
CREATE TABLE employees (id INT PRIMARY KEY, name VARCHAR(100));
Answer:

A foreign key is a field (or collection of fields) in one table that uniquely identifies a row of another table, establishing a relationship between the two.

Example:
CREATE TABLE orders (
  order_id INT PRIMARY KEY,
  customer_id INT,
  FOREIGN KEY (customer_id) REFERENCES customers(id));
Answer:

A unique key constraint ensures that all values in a column are distinct from each other.

        
Example: 

CREATE TABLE users (username VARCHAR(50) UNIQUE);
Answer:

SQL is a language for managing databases, while MySQL is a specific database management system that uses SQL.

Answer:

Normalization is the process of organizing data to minimize redundancy. Types include:
1NF (First Normal Form)
2NF (Second Normal Form)
3NF (Third Normal Form)

Answer:

Denormalization is the process of combining tables to improve read performance, often at the expense of write performance.

Answer:

An index is a database object that improves the speed of data retrieval operations on a table.

        
Example: 
CREATE INDEX idx_name ON table_name(column_name);
Answer:

A clustered index sorts and stores the data rows in the table based on the indexed column(s), while a non-clustered index creates a separate object that points to the data rows.

Answer:

A view is a virtual table based on the result of a query. It does not store data physically and can simplify complex queries.

Example:
CREATE VIEW view_name AS SELECT column1, column2 FROM table_name;
Answer:

A stored procedure is a precompiled collection of SQL statements that can be executed as a single unit and can be re-used again which gets saved in the cache.

Example:

CREATE PROCEDURE proc_name AS
BEGIN
  SELECT * FROM table_name;
END;
Answer:

A trigger is a special type of stored procedure that automatically runs when certain events occur in a table.

Example:
CREATE TRIGGER trigger_name
AFTER INSERT ON table_name
FOR EACH ROW
BEGIN
  INSERT INTO log_table (log_entry) VALUES ('Row inserted');
END;

Answer:

A transaction is a sequence of operations performed as a single logical unit of work. ACID properties ensure reliability:
Atomicity
Consistency
Isolation
Durability

Answer:

UNION combines the result of two queries and removes duplicates, while UNION ALL includes all duplicates.

Example:
SELECT column1 FROM table1
UNION
SELECT column1 FROM table2;
Answer:

A subquery is a query nested inside another query.

Example:
SELECT name FROM employees WHERE id IN (SELECT employee_id FROM orders);
Answer:

INNER JOIN returns only matching rows, while LEFT JOIN returns all rows from the left table and matched rows from the right.

        
Example: 
SELECT a.column1, b.column2 
FROM table_a a 
LEFT JOIN table_b b ON a.id = b.a_id;
Answer:

Indexes speed up data retrieval. Advantages include improved query performance and faster search results.

Answer:

A composite key is a primary key made up of two or more columns to uniquely identify a record.

        
Example:
CREATE TABLE orders (
  order_id INT,
  product_id INT,
  PRIMARY KEY (order_id, product_id));
Answer:

You can find duplicates using GROUP BY and HAVING clauses.

        
Example: 
SELECT column1, COUNT(*) 
FROM table_name 
GROUP BY column1 
HAVING COUNT(*) > 1;
Answer:

A self-join is a join of a table to itself.

   
Example:    
SELECT a.name, b.name 
FROM employees a, employees b 
WHERE a.manager_id = b.id;
Answer:

Aggregate functions perform calculations on a set of values and return a single value. Examples include SUM(), AVG(), COUNT(), MAX(), and MIN().

  
Example:    
SELECT COUNT(*) FROM employees;
Answer:

Data types define the type of data a column can hold, such as INT, VARCHAR, DATE, etc.

Answer:

Constraints enforce rules on data in a table. Types include: NOT NULL UNIQUE PRIMARY KEY FOREIGN KEY

        
Example:  
CREATE TABLE users (
  id INT PRIMARY KEY,
  email VARCHAR(100) UNIQUE);
Answer:

Partitioning divides a table into smaller, more manageable pieces while still being treated as a single table.

Answer:

Optimization techniques include using indexes, avoiding SELECT *, and analyzing execution plans.

Answer:

A CTE is a temporary result set that you can reference within a SELECT, INSERT, UPDATE, or DELETE statement.

    
Example:      
WITH cte_name AS (
  SELECT column1 FROM table_name
)
SELECT * FROM cte_name;
Answer:

ROLLUP and CUBE are used to generate subtotals and grand totals in query results.

        
Example: 
SELECT department, SUM(salary)
FROM employees
GROUP BY department WITH ROLLUP;
Answer:

Window functions perform calculations across a set of rows related to the current row without collapsing the result set.

        
Example: 
SELECT employee_id, salary, AVG(salary) OVER (PARTITION BY department_id) AS avg_department_salary
FROM employees;
Answer:

Dynamic SQL is SQL code that is generated and executed at runtime. It is useful for building queries dynamically based on user input.

        
Example:   
EXECUTE IMMEDIATE 'SELECT * FROM ' || table_name;
Answer:

Indexes speed up data retrieval but can slow down data insertion and updates due to the overhead of maintaining the index.

Answer:

A materialized view stores the result of a query physically, allowing for faster access but requiring maintenance to keep it updated.

        
Example:  
CREATE MATERIALIZED VIEW mv_name AS SELECT * FROM table_name;
Answer:

You can use TRY...CATCH blocks (in some databases like SQL Server) to handle errors.

        
Example:   
BEGIN TRY
  -- SQL statements
END TRY
BEGIN CATCH
  -- Error handling
END CATCH;
Answer:

A deadlock occurs when two or more transactions are waiting for each other to release locks. You can resolve it by using proper transaction management and timeout settings.

Answer:

You can use the LIMIT clause (or TOP in SQL Server).

Example: 
SELECT * FROM table_name LIMIT N;  -- For MySQL
SELECT TOP N * FROM table_name;    -- For SQL Server
Answer:

You can use a CTE or a temporary table to identify and delete duplicates.

 Example:
 WITH cte AS (
  SELECT *,
         ROW_NUMBER() OVER (PARTITION BY column1 ORDER BY (SELECT NULL)) AS rn
  FROM table_name
)
DELETE FROM cte WHERE rn > 1;
Answer:

You can use a CASE statement in the UPDATE query.

Example: 
UPDATE table_name
SET column_name = CASE 
  WHEN condition1 THEN value1 
  WHEN condition2 THEN value2 
  END
WHERE condition;
Answer:

Use BEGIN TRANSACTION, COMMIT, and ROLLBACK to manage transactions.

 Example: 
 BEGIN TRANSACTION;
-- SQL statements
COMMIT;  -- or ROLLBACK;
Answer:

Analyze the query plan, check for missing indexes, optimize the query, and consider database statistics.

Answer:
SELECT MAX(salary) 
FROM employees 
WHERE salary < (SELECT MAX(salary) FROM employees);
Answer:
 
 SELECT * FROM employees WHERE salary > (SELECT AVG(salary) FROM employees);
Answer:
 
SELECT *
FROM (SELECT year, department, salary FROM salaries) AS SourceTable
PIVOT
(SUM(salary) FOR department IN ([HR], [IT], [Sales])) AS PivotTable;
Answer:
 
SELECT MONTH(sale_date) AS sale_month, SUM(amount) AS total_sales
FROM sales
GROUP BY MONTH(sale_date);
Answer:

Use the bcp command in SQL Server or the SELECT ... INTO OUTFILE statement in MySQL.

Example:
SELECT * INTO OUTFILE '/path/to/file.csv'
FIELDS TERMINATED BY ',' 
ENCLOSED BY '"'
LINES TERMINATED BY '\n'
FROM table_name;
Answer:

                                
SELECT e.name, e.salary, d.department_name
FROM employees e
JOIN departments d ON e.department_id = d.department_id
WHERE e.salary > (
SELECT AVG(salary)
FROM employees
WHERE department_id = e.department_id); 

Answer:

                                
SELECT o.customer_id, SUM(o.amount) AS total_spent
FROM orders o
WHERE o.order_date >= DATEADD(MONTH, -6, GETDATE())
GROUP BY o.customer_id
HAVING COUNT(o.order_id) > 5;

Answer:

(This should be based on your personal experience.)

Answer:

Follow online courses, read documentation, and participate in forums or user groups.

Answer:

(This should be based on your personal experience.)

Answer:

Use open communication, listen to all viewpoints, and seek a collaborative solution.

Answer:

Use query execution plans, logging, and SQL profiling tools to analyze and debug queries.